Stoichiometry of a Chemical
Reaction
Post-Lab Report
(a) Report the collected data
with the correct uncertainty.
|
Trial |
Mass H2C2O4 (g) |
Initial
Volume NaOH(mL) |
Final Volume NaOH(mL) |
(NaOH) mol/L |
|
1 |
0.1 |
3 |
20.4 |
0.100 |
|
2 |
0.1996 |
3.5 |
34.6 |
0.100 |
|
3 |
0.1959 |
2.5 |
33.5 |
0.100 |
(b) Calculate the moles of each
reactant used (Show one sample calculation).
Mole
= Mass/Molar mass
Molar Mass of (H2C2O4)
(H=1*2 + C=2*12 + O=4*16) =90
g/mol
Mole
= 0.1g/90 g/mol = 0.00111
|
Trial |
Mol H2C2O4 |
Mol NaOH |
Mol (H2C2O4)/ mol (NaOH) |
|
1 |
0.00111 |
0.03 |
0.037 |
|
2 |
0.00223 |
0.035 |
0.064 |
|
3 |
0.00227 |
0.025 |
0.091 |
(c) Report the balanced chemical
equation.
H2C2O4 (aq) +NaOH(aq) Na(g)
+ H3C2O5 (g)
Report
The
balanced chemical equation is an indication that the both reduction and
addition took place. The sodium hydroxide was reduced into the sodium metal,
thus reducing its mass. However, the crystalline carboxyl acid received two
elements of carbon and four elements of oxygen resulting into a different
compound H3C2O5
(g) which
is gaseous in nature thus increasing in weight.
Additional articles
Book Report By Written By Published Academic Writers Are you thinking: “someone please write my book report for me†but at the same time you’re looking for legit assistance? Whether it’s an AP Euro book report or an English one- we’l...Write-My-Book-Report-For-Me-Professionally …
Read ArticleDiscussion on Robert Wood Johnson Foundation Committee Initiative and Institute of Medicine (IOM) that led to "Future of Nursing: Leading Change, Advancing Health." The work of the Robert Wood Johnson Foundation Committee Initiative in collabo...Implementation-of-the-IOM-Future-of-Nursing-Report …
Read ArticleVarious newspapers develop their headlines along the basis of what particular set of wordings would cause trending in the social media platforms and increase the number of likes and visits to their websites and pages. Content focus and maintenance...Rise-of-Tabloid-News …
Read Article