Stoichiometry of a Chemical
Reaction
Post-Lab Report
(a) Report the collected data
with the correct uncertainty.
|
Trial |
Mass H2C2O4 (g) |
Initial
Volume NaOH(mL) |
Final Volume NaOH(mL) |
(NaOH) mol/L |
|
1 |
0.1 |
3 |
20.4 |
0.100 |
|
2 |
0.1996 |
3.5 |
34.6 |
0.100 |
|
3 |
0.1959 |
2.5 |
33.5 |
0.100 |
(b) Calculate the moles of each
reactant used (Show one sample calculation).
Mole
= Mass/Molar mass
Molar Mass of (H2C2O4)
(H=1*2 + C=2*12 + O=4*16) =90
g/mol
Mole
= 0.1g/90 g/mol = 0.00111
|
Trial |
Mol H2C2O4 |
Mol NaOH |
Mol (H2C2O4)/ mol (NaOH) |
|
1 |
0.00111 |
0.03 |
0.037 |
|
2 |
0.00223 |
0.035 |
0.064 |
|
3 |
0.00227 |
0.025 |
0.091 |
(c) Report the balanced chemical
equation.
H2C2O4 (aq) +NaOH(aq) Na(g)
+ H3C2O5 (g)
Report
The
balanced chemical equation is an indication that the both reduction and
addition took place. The sodium hydroxide was reduced into the sodium metal,
thus reducing its mass. However, the crystalline carboxyl acid received two
elements of carbon and four elements of oxygen resulting into a different
compound H3C2O5
(g) which
is gaseous in nature thus increasing in weight.
Additional articles
A very famous saying goes that “You are what you eat†and it is right in that the human body can take what a person is eating and make them work for or against the individual. When it comes to instances that a person is taking part in a wellne...Physical-Fitness-and-Nutrition …
Read ArticleHave you met the objectives of the course? The goals of the course have been fulfilled efficiently in the process of learning. I have been able to use the graphics effectively, developed a clear and efficient writing style and organized informa...Technical-Writing:-Final-Thoughts …
Read ArticleIntroduction The death penalty punishment has been an issue that has raised controversy over time not just in the United States but also with the rest of the world. The public and also law enforcers have remained split on the issue with activi...Finding-common-ground-essay …
Read Article